So let's start with the area first. And that area is pretty straightforward. So area is 44 square inches. 11 4 area of regular polygons and composite figures. This method will work here if you are given (or can find) the lengths for each side as well as the length from the midpoint of each side to the center of the pentagon. A polygon is a closed figure made up of straight lines that do not overlap. With each side equal to 5. For any three dimensional figure you can find surface area by adding up the area of each face.
This is a one-dimensional measurement. It is simple to find the area of the 5 rectangles, but the 2 pentagons are a little unusual. You would get the area of that entire rectangle. Created by Sal Khan and Monterey Institute for Technology and Education. And that actually makes a lot of sense. And let me get the units right, too. So this is going to be square inches. 11 4 area of regular polygons and composite figures of speech. This resource is perfect to help reinforce calculating area of triangles, rectangles, trapezoids, and parallelograms. So area's going to be 8 times 4 for the rectangular part. Area of polygon in the pratice it harder than this can someone show way to do it? It's measuring something in two-dimensional space, so you get a two-dimensional unit. So the perimeter-- I'll just write P for perimeter.
So this is going to be 32 plus-- 1/2 times 8 is 4. That's the triangle's height. First, you have this part that's kind of rectangular, or it is rectangular, this part right over here. What is a perimeter? What exactly is a polygon? 11 4 area of regular polygons and composite figures are congruent. In either direction, you just see a line going up and down, turn it 45 deg. So the area of this polygon-- there's kind of two parts of this. And that makes sense because this is a two-dimensional measurement. You have the same picture, just narrower, so no.
Without seeing what lengths you are given, I can't be more specific. Try making a pentagon with each side equal to 10. So we have this area up here. 8 inches by 3 inches, so you get square inches again. I don't know what lenghts you are given, but in general I would try to break up the unusual polygon into triangles (or rectangles). Students must find the area of the greater, shaded figure then subtract the smaller shape within the figure. Over the course of 14 problems students must evaluate the area of shaded figures consisting of polygons. And so let's just calculate it. It's only asking you, essentially, how long would a string have to be to go around this thing. Would finding out the area of the triangle be the same if you looked at it from another side? A pentagonal prism 7 faces: it has 5 rectangles on the sides and 2 pentagons on the top and bottom.
So The Parts That Are Parallel Are The Bases That You Would Add Right? So you have 8 plus 4 is 12. So once again, let's go back and calculate it. I don't want to confuse you. So plus 1/2 times the triangle's base, which is 8 inches, times the triangle's height, which is 4 inches. Because over here, I'm multiplying 8 inches by 4 inches. Try making a triangle with two of the sides being 17 and the third being 16. Includes composite figures created from rectangles, triangles, parallelograms, and trapez. It's going to be equal to 8 plus 4 plus 5 plus this 5, this edge right over here, plus-- I didn't write that down. If you took this part of the triangle and you flipped it over, you'd fill up that space. This gives us 32 plus-- oh, sorry.